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Proof step 3 from proof to-adrs-eq-one (previous step)

adr = @(m, m0, m1) ⊦ adr ' = lax.to-adr(n) ↔ lax = @(m0, m1) ' ∧ m = n

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
@(m, m0, m1) ' = lax.to-adr(n) ⊦ lax = @(m0, m1) ' ∧ m = n

Rule argument

Additional information

Used simplifier rules: to-adrs-one: ⊦ ladr '.to-adr(n) = @(n, ladr.off, ladr.size) ';% ⊦ adr ' = adr0 ' ↔ adr = adr0; (s)% ⊦ @(m, m0).size = m0; (s)% ⊦ @(m, m0).off = m; (s)