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Proof step 4 from proof to-adrs-eq-one (previous step)

@(m, m0, m1) ' = lax.to-adr(n) ⊦ lax = @(m0, m1) ' ∧ m = n

User applied rule constructor cut

And obtained the following new goals

Proof step 5:
@(m, m0, m1) ' = lax.to-adr(n), lax = ladr + lax0 ⊦ lax = @(m0, m1) ' ∧ m = n

Rule argument

var: lax

Additional information

Used simplifier rules: adrs-empty: ⊦ ([]).to-adr(n) = [];%laddress-list freely generated by [], +;;% ⊦ adr ' ≠ []; (s)