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Proof step 10 from proof restrict-add-other (previous step)

adr = @(m3, m4, m5) ⊦ m3 = m ∧ (adr = @(m0, m1, m2) ∨ adr ∈ as) ↔ adr ∈ as | m, m = m0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information