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Proof step 11 from proof restrict-add-other (previous step)

⊦ m3 = m ∧ (@(m, m4, m5) = @(m0, m1, m2) ∨ @(m, m4, m5) ∈ as) ↔ @(m3, m4, m5) ∈ as | m, m = m0

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel> name: restrict-leb seq: ⊦ adr ∈ as | n ↔ adr.lnum = n ∧ adr ∈ as subst: [n, as, adr] → [m, as, @(m3, m4, m5)] flags: <all paths>

Additional information

Used simplifier rules: ⊦ @(m, m0, m1).lnum = m; (s)% ⊦ @(m, m0, m1) = @(m2, m3, m4) ↔ m = m2 ∧ m0 = m3 ∧ m1 = m4; (ws) Used terms: m, as, @(m3, m4, m5)