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Proof step 6 from proof restrict-add-other (previous step)

⊦ adr ∈ (as ++ @(m0, m1, m2)) | m ↔ adr ∈ as | m, m = m0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 7:
⊦ adr ∈ as | n ↔ adr.lnum = n ∧ adr ∈ as
Proof step 8:
⊦ adr.lnum = m ∧ adr ∈ as ++ @(m0, m1, m2) ↔ adr ∈ as | m, m = m0

Rule argument

spec: <toplevel> name: restrict-leb seq: ⊦ adr ∈ as | n ↔ adr.lnum = n ∧ adr ∈ as subst: [n, as, adr] → [m, as ++ @(m0, m1, m2), adr] flags: <all paths>

Additional information

Used terms: m, as ++ @(m0, m1, m2), adr