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Proof step 8 from proof restrict-add-other (previous step)

⊦ adr.lnum = m ∧ adr ∈ as ++ @(m0, m1, m2) ↔ adr ∈ as | m, m = m0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
⊦ adr.lnum = m ∧ (adr = @(m0, m1, m2) ∨ adr ∈ as) ↔ adr ∈ as | m, m = m0

Rule argument

Additional information

Used simplifier rules: ⊦ adr ∈ as ++ adr0 ↔ adr = adr0 ∨ adr ∈ as; (s)