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Proof step 12 from proof restrict-add (previous step)

@(m, m3, m4) = @(m0, m1, m2) ∨ m = m0 ∧ @(m0, m3, m4) ∈ as ⊦ m = m0 ∧ (@(m0, m3, m4) = @(m0, m1, m2) ∨ @(m0, m3, m4) ∈ as)

User applied rule case distinction

And closed the goal!

Rule argument

pos: left 1

Additional information

Used simplifier rules: ⊦ @(m, m0, m1) = @(m2, m3, m4) ↔ m = m2 ∧ m0 = m3 ∧ m1 = m4; (ws)