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Proof step 11 from proof restrict-add (previous step)

@(m, m3, m4) = @(m0, m1, m2) ∨ @(m, m3, m4).lnum = m0 ∧ @(m, m3, m4) ∈ as ⊦ m = m0 ∧ (@(m0, m3, m4) = @(m0, m1, m2) ∨ @(m0, m3, m4) ∈ as)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
@(m, m3, m4) = @(m0, m1, m2) ∨ m = m0 ∧ @(m0, m3, m4) ∈ as ⊦ m = m0 ∧ (@(m0, m3, m4) = @(m0, m1, m2) ∨ @(m0, m3, m4) ∈ as)

Rule argument

Additional information

Used simplifier rules: ⊦ @(m, m0, m1).lnum = m; (s)