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Proof step 9 from proof restrict-add (previous step)

@(m, m3, m4) = @(m0, m1, m2) ∨ @(m, m3, m4) ∈ as | m0 ⊦ m = m0 ∧ (@(m0, m3, m4) = @(m0, m1, m2) ∨ @(m0, m3, m4) ∈ as)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 10:
⊦ adr ∈ as | n ↔ adr.lnum = n ∧ adr ∈ as
Proof step 11:
@(m, m3, m4) = @(m0, m1, m2) ∨ @(m, m3, m4).lnum = m0 ∧ @(m, m3, m4) ∈ as ⊦ m = m0 ∧ (@(m0, m3, m4) = @(m0, m1, m2) ∨ @(m0, m3, m4) ∈ as)

Rule argument

spec: <toplevel> name: restrict-leb seq: ⊦ adr ∈ as | n ↔ adr.lnum = n ∧ adr ∈ as subst: [n, as, adr] → [m0, as, @(m, m3, m4)] flags: <all paths>

Additional information

Used terms: m0, as, @(m, m3, m4)