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Proof step 6 from proof restrict-add (previous step)

⊦ adr.lnum = m0 ∧ adr ∈ as ++ @(m0, m1, m2) ↔ adr = @(m0, m1, m2) ∨ adr ∈ as | m0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
adr = @(m0, m1, m2) ∨ adr ∈ as | m0 ⊦ adr.lnum = m0 ∧ (adr = @(adr.lnum, m1, m2) ∨ adr ∈ as)

Rule argument

Additional information

Used simplifier rules: restrict-leb: ⊦ adr ∈ as | n ↔ adr.lnum = n ∧ adr ∈ as;% ⊦ adr ∈ as ++ adr0 ↔ adr = adr0 ∨ adr ∈ as; (s)% ⊦ adr ≠ adr0 → (adr ∈ as ++ adr0 ↔ adr ∈ as); (s)