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Proof step 7 from proof restrict-add (previous step)

adr = @(m0, m1, m2) ∨ adr ∈ as | m0 ⊦ adr.lnum = m0 ∧ (adr = @(adr.lnum, m1, m2) ∨ adr ∈ as)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 8:
adr = @(m, m3, m4), adr = @(m0, m1, m2) ∨ adr ∈ as | m0 ⊦ m = m0 ∧ (adr = @(m, m1, m2) ∨ adr ∈ as)

Rule argument

spec: address-data name: elim seq: ⊦ (m = adr.lnum ∧ m0 = adr.pos) ∧ m1 = adr.size ↔ adr = @(m, m0, m1) subst: [adr, m, m0, m1] → [adr, m, m3, m4]

Additional information

Used simplifier rules: ⊦ (m = adr.lnum ∧ m0 = adr.pos) ∧ m1 = adr.size ↔ adr = @(m, m0, m1); (elim) Used terms: adr, m, m3, m4