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Proof step 3 from proof restrict-del-other (previous step)

⊦ m = n, (as -- @(m, m0, m1)) | n = as | n

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ as = as0 ↔ (∀ adr. adr ∈ as ↔ adr ∈ as0)
Proof step 5:
⊦ m = n, ∀ adr. adr ∈ (as -- @(m, m0, m1)) | n ↔ adr ∈ as | n

Rule argument

spec: set-basic, inst: address-store name: Extension seq: ⊦ as = as0 ↔ (∀ adr. adr ∈ as ↔ adr ∈ as0) subst: [as0, as] → [as | n, (as -- @(m, m0, m1)) | n] flags: <all paths>

Additional information

Used terms: as | n, (as -- @(m, m0, m1)) | n