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Proof step 5 from proof restrict-del-other (previous step)

⊦ m = n, ∀ adr. adr ∈ (as -- @(m, m0, m1)) | n ↔ adr ∈ as | n

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
⊦ adr ∈ (as -- @(m, m0, m1)) | n ↔ adr ∈ as | n, m = n

Rule argument

Additional information