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Proof step 10 from proof abs-nodes-aligned-headersize-h (previous step)

buf = buf0 + buf1, abs-nodes(buf1, m + # buf0, [], [], weak), abs-padding(buf0), ∀ buf0, m, x, lax, weak. # buf0 < # buf → abs-nodes(buf0, m, x, lax, weak) → is-aligned(# buf0, NODE_HEADER_SIZE) ⊦ is-aligned(# buf, NODE_HEADER_SIZE)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
abs-nodes(buf1, m + # buf0, [], [], weak), abs-padding(buf0), ∀ buf2, m, x, lax, weak. # buf2 < #(buf0 + buf1) → abs-nodes(buf2, m, x, lax, weak) → is-aligned(# buf2, NODE_HEADER_SIZE) ⊦ is-aligned(# buf0 + # buf1, NODE_HEADER_SIZE)

Rule argument

Additional information

Used simplifier rules: append-a: ⊦ (buf + buf0) + buf1 = buf + buf0 + buf1; from specification array-splice[buffer]% ⊦ #(buf + buf0) = # buf + # buf0; (s)