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Proof step 9 from proof abs-nodes-aligned-headersize-h (previous step)

buf = mkbuf(0) ∨ buf = buf0 + buf1 ∧ abs-padding(buf0) ∧ abs-nodes(buf1, m + # buf0, [], [], weak) ∨ weak ∧ abs-failed(buf), ∀ buf0, m, x, lax, weak. # buf0 < # buf → abs-nodes(buf0, m, x, lax, weak) → is-aligned(# buf0, NODE_HEADER_SIZE) ⊦ is-aligned(# buf, NODE_HEADER_SIZE)

User applied rule case distinction

And obtained the following new goals

Proof step 10:
buf = buf0 + buf1, abs-nodes(buf1, m + # buf0, [], [], weak), abs-padding(buf0), ∀ buf0, m, x, lax, weak. # buf0 < # buf → abs-nodes(buf0, m, x, lax, weak) → is-aligned(# buf0, NODE_HEADER_SIZE) ⊦ is-aligned(# buf, NODE_HEADER_SIZE)

Rule argument

pos: left 1

Additional information

Used simplifier rules: ⊦ abs-failed(buf) → is-aligned(# buf, NODE_HEADER_SIZE); (ss)% ⊦ # mkbuf(n) = n; (s)% ⊦ NODE_HEADER_SIZE ≠ 0; (s)%n ≠ 0 ⊦ is-aligned(0, n); (s)