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Proof step 4 from proof abs-nodes-beyond-no-address-h (previous step)

abs-nodes(buf, m, x, lax, boolvar), @(m0, m1) ∈ lax, # buf + m ≤ m0, ∀ buf0, m, x, lax, boolvar, m0, m1. # buf0 < # buf → abs-nodes(buf0, m, x, lax, boolvar) ∧ @(m0, m1) ∈ lax ∧ # buf0 + m ≤ m0 → false ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
abs-nodes(buf, m, x, lax, boolvar), @(m0, m1) ∈ lax, # buf + m ≤ m0, ∀ buf0, m, x, lax, boolvar, m0, m1. # buf0 < # buf → abs-nodes(buf0, m, x, lax, boolvar) ∧ @(m0, m1) ∈ lax ∧ # buf0 + m ≤ m0 → false ⊦

Proof step 4 from proof abs-nodes-beyond-no-address-h (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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