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Proof step 5 from proof abs-nodes-beyond-no-address-h (previous step)

abs-nodes(buf, m, x, lax, boolvar), @(m0, m1) ∈ lax, # buf + m ≤ m0, ∀ buf0, m, x, lax, boolvar, m0, m1. # buf0 < # buf → abs-nodes(buf0, m, x, lax, boolvar) ∧ @(m0, m1) ∈ lax ∧ # buf0 + m ≤ m0 → false ⊦

User applied rule constructor cut

And obtained the following new goals

Proof step 6:
x = nd + x0, abs-nodes(buf, m, x, lax, boolvar), @(m0, m1) ∈ lax, # buf + m ≤ m0, ∀ buf0, m, x, lax, boolvar, m0, m1. # buf0 < # buf → abs-nodes(buf0, m, x, lax, boolvar) ∧ @(m0, m1) ∈ lax ∧ # buf0 + m ≤ m0 → false ⊦

Rule argument

var: x

Additional information

Used simplifier rules: abs-nodes-elems-empty-adr-empty-h: ⊦ abs-nodes(buf, m, [], lax, weak) → lax = [];%list freely generated by [], +;;% ⊦ ¬ ladr ∈ []; (s)