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Proof step 6 from proof abs-nodes-beyond-no-address-h (previous step)

x = nd + x0, abs-nodes(buf, m, x, lax, boolvar), @(m0, m1) ∈ lax, # buf + m ≤ m0, ∀ buf0, m, x, lax, boolvar, m0, m1. # buf0 < # buf → abs-nodes(buf0, m, x, lax, boolvar) ∧ @(m0, m1) ∈ lax ∧ # buf0 + m ≤ m0 → false ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
abs-nodes(buf, m, nd ' + x0, lax, boolvar), @(m0, m1) ∈ lax, # buf + m ≤ m0, ∀ buf0, m, x, lax, boolvar, m0, m1. # buf0 < # buf → abs-nodes(buf0, m, x, lax, boolvar) ∧ @(m0, m1) ∈ lax ∧ # buf0 + m ≤ m0 → false ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ a + x = a ' + x; (s)