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Proof step 13 from proof abs-nodes-one-h (previous step)

⊦ (∃ buf0, buf1. buf = buf0 + buf1 ∧ ( abs-padding(buf0) ∧ abs-nodes(buf1, m + # buf0, a ', @(m0, m1) ' + lax0, weak) ∨ m0 = m ∧ m1 = # buf0 ∧ abs-node(buf0, a) ∧ abs-nodes(buf1, m + # buf0, [], lax0, weak))) ↔ (∃ buf0, buf1. buf = buf0 + buf1 ∧ ( abs-padding(buf0) ∧ abs-nodes(buf1, m + # buf0, a ', @(m0, m1) ' + lax0, weak) ∨ @(m0, m1) ' + lax0 = @(m, 2 * NODE_HEADER_SIZE + a.alignedsize) ' ∧ abs-node(buf0, a) ∧ abs-nodes(buf1, m + # buf0, [], [], weak)))

User applied rule case distinction

And obtained the following new goals

Rule argument

pos: right 1

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