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Proof step 18 from proof abs-nodes-one-h (previous step)

∃ buf0, buf1. buf = buf0 + buf1 ∧ ( abs-padding(buf0) ∧ abs-nodes(buf1, m + # buf0, a ', @(m0, m1) ' + lax0, weak) ∨ @(m0, m1) ' + lax0 = @(m, 2 * NODE_HEADER_SIZE + a.alignedsize) ' ∧ abs-node(buf0, a) ∧ abs-nodes(buf1, m + # buf0, [], [], weak)) ⊦ ∃ buf0, buf1. buf = buf0 + buf1 ∧ ( abs-padding(buf0) ∧ abs-nodes(buf1, m + # buf0, a ', @(m0, m1) ' + lax0, weak) ∨ m0 = m ∧ m1 = # buf0 ∧ abs-node(buf0, a) ∧ abs-nodes(buf1, m + # buf0, [], lax0, weak))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 19:
abs-padding(buf1) ∧ abs-nodes(buf0, m + # buf1, a ', @(m0, m1) ' + lax0, weak) ∨ @(m0, m1) ' + lax0 = @(m, 2 * NODE_HEADER_SIZE + a.alignedsize) ' ∧ abs-node(buf1, a) ∧ abs-nodes(buf0, m + # buf1, [], [], weak) ⊦ ∃ buf3, buf2. buf1 + buf0 = buf3 + buf2 ∧ ( abs-padding(buf3) ∧ abs-nodes(buf2, m + # buf3, a ', @(m0, m1) ' + lax0, weak) ∨ m0 = m ∧ m1 = # buf3 ∧ abs-node(buf3, a) ∧ abs-nodes(buf2, m + # buf3, [], lax0, weak))

Proof step 18 from proof abs-nodes-one-h (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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