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Proof step 3 from proof abs-nodes-padding-prefix (previous step)

abs-padding(buf0) ⊦ abs-nodes(buf0 + buf1, m, x, lax, weak) ↔ abs-nodes(buf1, m + # buf0, x, lax, weak)

User applied rule constructor cut

And obtained the following new goals

Proof step 4:
x = [], abs-padding(buf0) ⊦ abs-nodes(buf0 + buf1, m, x, lax, weak) ↔ abs-nodes(buf1, m + # buf0, x, lax, weak)
Proof step 7:
x = nd + x0, abs-padding(buf0) ⊦ abs-nodes(buf0 + buf1, m, x, lax, weak) ↔ abs-nodes(buf1, m + # buf0, x, lax, weak)

Rule argument

var: x

Additional information

Used simplifier rules: list freely generated by [], +;;