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Proof step 7 from proof abs-nodes-padding-prefix (previous step)

x = nd + x0, abs-padding(buf0) ⊦ abs-nodes(buf0 + buf1, m, x, lax, weak) ↔ abs-nodes(buf1, m + # buf0, x, lax, weak)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
abs-padding(buf0) ⊦ abs-nodes(buf0 + buf1, m, nd ' + x0, lax, weak) ↔ abs-nodes(buf1, m + # buf0, nd ' + x0, lax, weak)

Rule argument

Additional information

Used simplifier rules: ⊦ a + x = a ' + x; (s)