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Proof step 13 from proof abs-nodes-unique-strong-h (previous step)

∃ buf0, buf1. buf = buf0 + buf1 ∧ ( abs-padding(buf0) ∧ abs-nodes(buf1, m + # buf0, nd ' + x, lax0, false) ∨ lax0 ≠ [] ∧ lax0.head.off = m ∧ lax0.head.size = # buf0 ∧ abs-node(buf0, nd) ∧ abs-nodes(buf1, m + # buf0, x, lax0.tail, false)), ∀ buf0, m, x0, lax0, x1, lax1, boolvar1. # buf0 < # buf → abs-nodes(buf0, m, x0, lax0, false) → (abs-nodes(buf0, m, x1, lax1, boolvar1) ↔ x0 = x1 ∧ lax0 = lax1) ⊦ abs-nodes(buf, m, x1, lax1, boolvar1) ↔ nd ' + x = x1 ∧ lax0 = lax1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
abs-padding(buf1) ∧ abs-nodes(buf0, m + # buf1, nd ' + x, lax0, false) ∨ lax0 ≠ [] ∧ lax0.head.off = m ∧ lax0.head.size = # buf1 ∧ abs-node(buf1, nd) ∧ abs-nodes(buf0, lax0.head.off + # buf1, x, lax0.tail, false), ∀ buf2, m, x0, lax0, x1, lax1, boolvar1. # buf2 < #(buf1 + buf0) → abs-nodes(buf2, m, x0, lax0, false) → (abs-nodes(buf2, m, x1, lax1, boolvar1) ↔ x0 = x1 ∧ lax0 = lax1) ⊦ abs-nodes(buf1 + buf0, m, x1, lax1, boolvar1) ↔ nd ' + x = x1 ∧ lax0 = lax1

Proof step 13 from proof abs-nodes-unique-strong-h (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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