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Theorem abs-nodes-unique-strong-h
⊦ abs-nodes(buf, m, x0, lax0, false) → (abs-nodes(buf, m, x1, lax1, boolvar1) ↔ x0 = x1 ∧ lax0 = lax1)
Type: A user defined theorem
Validity: The proof is valid.
Features: s, ls,
Comment:
Used by:
abs-nodes-add-crash-aligned
,
abs-nodes-add-crash-aligned-h
,
abs-nodes-add-crash-aligned-nodes
,
abs-nodes-append-empty-h
,
abs-nodes-at-least-flashsize
,
abs-nodes-no-padding-last
,
abs-nodes-no-padding-rec
,
abs-nodes-prefix-elim
,
abs-nodes-split
,
abs-nodes-split-h
,
abs-nodes-strengthen
,
abs-nodes-strong-imp-weak-h
,
abs-nodes-unique-strong
,
Used by units in proved state:
persistence-refine
,
Proof exists?: Yes
View
the proof
Infos about the proof
Proved?: Yes
Interactions: 13
Proof steps: 34
Used lemmas:
abs-nodes-nospace-h
,
ls-abs-node-buf-size
,
abs-nodes-first-adr-explicit
,
abs-nodes-rec
,
abs-nodes-padding-prefix
,
abs-nodes-mkbuf0-empty-h
,
abs-nodes-base
,
abs-nodes-elems-empty-adr-empty-h
,
Used spec theorems:
Used simplifier rules:
array-splice
/buffer/
append-eq-emptyar
list
/
c
laddress
/
elim
list
/laddress-list/
in-rec
list
/laddress-list/
in-14
nat-basic
/
add-base
abs-node
/
abs-padding-mkbuf0
list
/laddress-list/
c
list
/
e-01
abs-node
/
abs-node-abs-failed
nat-basic
/
zero
array-splice
/buffer/
append-eq-left
abs-node
/
abs-node-abs-node
abs-node
/
abs-node-no-abs-padding
list
/laddress-list/
e-01
list-data
/laddress-list/
elim-list-c
list
/laddress-list/
app-08
list
/
app-08
array-splice
/buffer/
append-len
array-splice
/buffer/
append-a
nat
/
lels
nat
/
le-add
abs-node
/
buf-size-zero
nat-basic
/
a
nat-basic
/
c
array
/buffer/
Size-mkarray
nat-basic
/
z-01
nat-mult
/
two-zero-01
node-header-size
/
nodeheader-notzero
nat-mult
/
mult-a
nat-mult
/
mult-c
laddress
/
inj
list
/
a
list
/
c-06
list
/laddress-list/
a
list
/laddress-list/
c-06