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Theorem abs-node-no-abs-padding
⊦ abs-node(buf0, nd) ∧ buf0 + buf1 = buf + buf2 → ¬ abs-padding(buf)
Type: A user defined theorem
Validity: The proof is valid.
Features: s, ls,
Comment:
Used by:
Used by units in proved state:
abs-list
,
Proof exists?: Yes
View
the proof
Infos about the proof
Proved?: Yes
Interactions: 3
Proof steps: 5
Used lemmas:
abs-node
,
abs-padding
,
Used spec theorems:
array-splice
/buffer/
append-a
array-splice
/buffer/
append-inj
Used simplifier rules:
abs-node
/
lfw-is-encoded-nodeheader-size
encoding-fixed-size-nonempty
/encoding-node-header/
is-encoded-unique
node-header
/
inj
array-copy
/buffer/
subarray-elim