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Proof step 2 from proof abs-nodes-unique-strong-h (
previous step
)
abs-nodes(buf, m, x0, lax0, false) ⊦ abs-nodes(buf, m, x1, lax1, boolvar1) ↔ x0 = x1 ∧ lax0 = lax1
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 3
:
abs-nodes(buf, m, x0, lax0, false) ⊦ abs-nodes(buf, m, x1, lax1, boolvar1) ↔ x0 = x1 ∧ lax0 = lax1
Rule argument
Additional information