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Proof step 31 from proof abs-nodes-unique-strong-h (previous step)

# buf1 = nd.alignedsize + 2 * NODE_HEADER_SIZE, lax1 = ladr + lax3, abs-node(buf1, nd), abs-nodes(buf0, m + # buf1, x, lax2, false), ∀ buf2, m, x0, lax0, x1, lax1, boolvar1. # buf2 < #(buf1 + buf0) → abs-nodes(buf2, m, x0, lax0, false) → (abs-nodes(buf2, m, x1, lax1, boolvar1) ↔ x0 = x1 ∧ lax0 = lax1) ⊦ lax1 ≠ [] ∧ ladr.off = m ∧ ladr.size = # buf1 ∧ nd = nd0 ∧ abs-nodes(buf0, ladr.off + # buf1, x2, lax3, boolvar1) ↔ nd ' + x = nd0 ' + x2 ∧ @(m, # buf1) ' + lax2 = lax1, lax1 = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 32:
# buf1 = nd.alignedsize + 2 * NODE_HEADER_SIZE, abs-node(buf1, nd), abs-nodes(buf0, m + # buf1, x, lax2, false), ∀ buf2, m, x0, lax0, x1, lax1, boolvar1. # buf2 < #(buf1 + buf0) → abs-nodes(buf2, m, x0, lax0, false) → (abs-nodes(buf2, m, x1, lax1, boolvar1) ↔ x0 = x1 ∧ lax0 = lax1) ⊦ ladr.off = m ∧ ladr.size = # buf1 ∧ nd = nd0 ∧ abs-nodes(buf0, ladr.off + # buf1, x2, lax3, boolvar1) ↔ nd ' + x = nd0 ' + x2 ∧ @(m, # buf1) ' + lax2 = ladr ' + lax3

Rule argument

Additional information

Used simplifier rules: a: ⊦ (lax + lax0) + lax1 = lax + lax0 + lax1; from specification list[laddress-list]% ⊦ ladr ' + lax ≠ []; (s)% ⊦ ladr + lax = ladr ' + lax; (s)