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Proof step 1 from proof abs-node-abs-node (conclusion)

⊦ abs-node(buf0, nd0) ∧ buf0 + buf2 = buf1 + buf3 → (abs-node(buf1, nd1) ↔ buf0 = buf1 ∧ nd0 = nd1)

System applied rule normalize

And obtained the following new goals

Rule argument

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