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Proof step 2 from proof abs-node-abs-node (previous step)

buf0 + buf2 = buf1 + buf3, abs-node(buf0, nd0) ⊦ abs-node(buf1, nd1) ↔ buf0 = buf1 ∧ nd0 = nd1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
# buf = NODE_HEADER_SIZE, # buf5 = NODE_HEADER_SIZE, # buf6 = nd0.alignedsize, # buf4 = nd1.alignedsize, (buf5 + buf6 + validtrailer) + buf2 = (buf + buf4 + validtrailer) + buf3, is-encoded(nd0, subarray(buf6, 0, node-size-headerless(nd0))), is-encoded(nodeheader(node-size-headerless(nd0), false), buf5), is-encoded(nd1, subarray(buf4, 0, node-size-headerless(nd1))), is-encoded(nodeheader(node-size-headerless(nd1), false), buf) ⊦ buf5 + buf6 = buf + buf4 ∧ nd0 = nd1

Rule argument

Additional information

Used simplifier rules: abs-node: ⊦ abs-node(buf, nd) ↔ (∃ buf0, buf1. buf = buf0 + buf1 + validtrailer ∧ is-encoded(nodeheader(node-size-headerless(nd), false), buf0) ∧ is-encoded(nd, subarray(buf1, 0, node-size-headerless(nd))) ∧ # buf1 = nd.alignedsize);%append-a: ⊦ (buf + buf0) + buf1 = buf + buf0 + buf1; from specification array-splice[buffer]% ⊦ buf + buf0 = buf1 + buf0 ↔ buf = buf1; (s)%is-encoded-size: ⊦ is-encoded(ndhd, buf) → # buf = NODE_HEADER_SIZE; (forward) from specification encoding-fixed-size-nonempty[encoding-node-header]