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Proof step 2 from proof abs-node-no-abs-padding (previous step)

buf0 + buf1 = buf + buf2, abs-node(buf0, nd), abs-padding(buf) ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
# buf3 = NODE_HEADER_SIZE, # buf5 = NODE_HEADER_SIZE, # buf6 = nd.alignedsize, (buf5 + buf6 + validtrailer) + buf1 = (buf3 + buf4 + validtrailer) + buf2, is-aligned(# buf4, 2 * NODE_HEADER_SIZE), is-encoded(nd, subarray(buf6, 0, node-size-headerless(nd))), is-encoded(nodeheader(node-size-headerless(nd), false), buf5), is-encoded(nodeheader(# buf4, true), buf3) ⊦

Rule argument

Additional information

Used simplifier rules: abs-padding: ⊦ abs-padding(buf) ↔ (∃ buf0, buf1. buf = buf0 + buf1 + validtrailer ∧ is-encoded(nodeheader(# buf1, true), buf0) ∧ is-aligned(# buf1, 2 * NODE_HEADER_SIZE));%abs-node: ⊦ abs-node(buf, nd) ↔ (∃ buf0, buf1. buf = buf0 + buf1 + validtrailer ∧ is-encoded(nodeheader(node-size-headerless(nd), false), buf0) ∧ is-encoded(nd, subarray(buf1, 0, node-size-headerless(nd))) ∧ # buf1 = nd.alignedsize);%is-encoded-size: ⊦ is-encoded(ndhd, buf) → # buf = NODE_HEADER_SIZE; (forward) from specification encoding-fixed-size-nonempty[encoding-node-header]