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Proof step 1 from proof abs-node-unique (conclusion)

⊦ abs-node(buf, nd0) → (abs-node(buf, nd1) ↔ nd0 = nd1)

System applied rule normalize

And obtained the following new goals

Proof step 2:
abs-node(buf, nd0) ⊦ abs-node(buf, nd1) ↔ nd0 = nd1

Rule argument

Additional information