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Proof step 2 from proof abs-node-unique (previous step)

abs-node(buf, nd0) ⊦ abs-node(buf, nd1) ↔ nd0 = nd1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
# buf0 = NODE_HEADER_SIZE, # buf2 = NODE_HEADER_SIZE, # buf3 = nd0.alignedsize, # buf1 = nd1.alignedsize, buf2 + buf3 = buf0 + buf1, is-encoded(nd0, subarray(buf3, 0, node-size-headerless(nd0))), is-encoded(nodeheader(node-size-headerless(nd0), false), buf2), is-encoded(nd1, subarray(buf1, 0, node-size-headerless(nd1))), is-encoded(nodeheader(node-size-headerless(nd1), false), buf0) ⊦ nd0 = nd1

Rule argument

Additional information

Used simplifier rules: abs-node: ⊦ abs-node(buf, nd) ↔ (∃ buf0, buf1. buf = buf0 + buf1 + validtrailer ∧ is-encoded(nodeheader(node-size-headerless(nd), false), buf0) ∧ is-encoded(nd, subarray(buf1, 0, node-size-headerless(nd))) ∧ # buf1 = nd.alignedsize);%append-a: ⊦ (buf + buf0) + buf1 = buf + buf0 + buf1; from specification array-splice[buffer]% ⊦ buf + buf0 = buf1 + buf0 ↔ buf = buf1; (s)%is-encoded-size: ⊦ is-encoded(ndhd, buf) → # buf = NODE_HEADER_SIZE; (forward) from specification encoding-fixed-size-nonempty[encoding-node-header]