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Proof step 14 from proof lpt-free-unref-write (previous step)

lpt[n] = mklp(m2, m3, lpf0, m4), lpt[n, mklp(m, m0, lpf, m1)][n0] = mklp(m5, m6, LP_FREE, m7), n0 < # lpt, n < # lpt ∧ lpf = LP_FREE → m = 0, n < # lpt ∧ lpf0 = LP_FREE → m2 = 0, ∀ n. n < # lpt ∧ lpt[n].flags = LP_FREE → lpt[n].ref-size = 0 ⊦ m5 = 0, n0 = n

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 15:
lpt[n] = mklp(m2, m3, lpf0, m4), lpt[n0] = mklp(m5, m6, LP_FREE, m7), n0 < # lpt, n < # lpt ∧ lpf0 = LP_FREE → m2 = 0, n < # lpt ∧ lpf = LP_FREE → m = 0, ∀ n. n < # lpt ∧ lpt[n].flags = LP_FREE → lpt[n].ref-size = 0 ⊦ m5 = 0, n0 = n

Rule argument

Additional information

Used simplifier rules: ⊦ m ≠ n → lpt[n, lp][m] = lpt[m]; (s)