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Proof step 15 from proof lpt-free-unref-write (previous step)

lpt[n] = mklp(m2, m3, lpf0, m4), lpt[n0] = mklp(m5, m6, LP_FREE, m7), n0 < # lpt, n < # lpt ∧ lpf0 = LP_FREE → m2 = 0, n < # lpt ∧ lpf = LP_FREE → m = 0, ∀ n. n < # lpt ∧ lpt[n].flags = LP_FREE → lpt[n].ref-size = 0 ⊦ m5 = 0, n0 = n

Heuristic quantifier applied rule all left

And closed the goal!

Rule argument

pos: left 6 terms: n0

Additional information

Used simplifier rules: ⊦ mklp(n2, n3, lpf, m).flags = lpf; (s)% ⊦ mklp(n2, n3, lpf, m).ref-size = n2; (s) Used terms: n0