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Proof step 2 from proof set-less-ar0 (previous step)

ginval < # lpt, n ∈ ginval ⊦ n < # lpt

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
ginval < # lpt, n ∈ ginval, # lpt ≤ n ⊦ # ginval = 0, ginval = ∅

Rule argument

Additional information

Used simplifier rules: size-zero-01: ⊦ ns ≠ ∅ → # ns ≠ 0; (forward) from specification set-basic[nat-set]%ne-01: ⊦ n ∈ ns → ns ≠ ∅; (forward) from specification set-basic[nat-set]% ⊦ m < n ↔ ¬ n ≤ m; (ss)