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Proof step 3 from proof set-less-ar0 (previous step)

ginval < # lpt, n ∈ ginval, # lpt ≤ n ⊦ # ginval = 0, ginval = ∅

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ ns < n ↔ (∀ n0. n0 ∈ ns → n0 < n)
Proof step 5:
n ∈ ginval, # lpt ≤ n, ∀ n0. n0 ∈ ginval → n0 < # lpt ⊦ # ginval = 0, ginval = ∅

Rule argument

spec: oset, inst: nat-set name: Greater seq: ⊦ ns < n ↔ (∀ n0. n0 ∈ ns → n0 < n) subst: [n, ns] → [# lpt, ginval] flags: <all paths>

Additional information

Used terms: # lpt, ginval