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Proof step 9 from proof fids-cons-reduce (previous step)

∀ fid. fid ∈ fs0 ↔ fid ∈ tree0.fids ∨ fid ∈ ofh0.fids, ∀ fid. fid ∈ fs1 ↔ fid ∈ tree1.fids ∨ fid ∈ ofh1.fids ⊦ ∀ fid. (fid ∈ fs0 ↔ fid ∈ tree0.fids ∨ fid ∈ ofh0.fids) → (fid ∈ fs1 ↔ fid ∈ tree1.fids ∨ fid ∈ ofh1.fids)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
fid ∈ fs0 ↔ fid ∈ tree0.fids ∨ fid ∈ ofh0.fids, ∀ fid. fid ∈ fs1 ↔ fid ∈ tree1.fids ∨ fid ∈ ofh1.fids, ∀ fid. fid ∈ fs0 ↔ fid ∈ tree0.fids ∨ fid ∈ ofh0.fids ⊦ fid ∈ fs1 ↔ fid ∈ tree1.fids ∨ fid ∈ ofh1.fids

Proof step 9 from proof fids-cons-reduce (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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