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Theorem fids-cons-reduce
⊦ fids-cons(tree0, fs0, ofh0) → (fids-cons(tree1, fs1, ofh1) ↔ (∀ fid. (fid ∈ fs0 ↔ fid ∈ tree0.fids ∨ fid ∈ ofh0.fids) → (fid ∈ fs1 ↔ fid ∈ tree1.fids ∨ fid ∈ ofh1.fids)))
Type: A user defined theorem
Validity: The proof is valid.
Features: lss,
Comment:
Used by:
inv-close
,
inv-create
,
inv-link
,
inv-mkdir
,
inv-open
,
inv-read
,
inv-recover
,
inv-rmdir
,
inv-seek
,
inv-truncate
,
inv-unlink
,
inv-write
,
inv-writemeta
,
rename-fids
,
Used by units in proved state:
Proof exists?: Yes
View
the proof
Infos about the proof
Proved?: Yes
Interactions: 6
Proof steps: 12
Used lemmas:
Used spec theorems:
posix-base
/
fids-cons
Used simplifier rules: