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Proof step 12 from proof crash-exists-h (
previous step
)
⊦ fid ∈ fs, ∃ fs0. (∀ fid0. fid0 ∈ fs0 ↔ fid0 = fid ∧ fid ∈ fs) ∧ (∀ fid. fid ∈ fs0 → fs0[fid] = fs[fid])
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 13
:
⊦ fid ∈ fs, ∃ fs0. (∀ fid0. ¬ fid0 ∈ fs0) ∧ (∀ fid. fid ∈ fs0 → fs0[fid] = fs[fid])
Rule argument
Additional information