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Proof step 13 from proof crash-exists-h (previous step)

⊦ fid ∈ fs, ∃ fs0. (∀ fid0. ¬ fid0 ∈ fs0) ∧ (∀ fid. fid ∈ fs0 → fs0[fid] = fs[fid])

User applied rule exists right

And closed the goal!

Rule argument

pos: right 2 terms: ∅ abort: F discard: F computed: F

Additional information

Used simplifier rules: ⊦ ¬ fid ∈ ∅; (s) Used terms: ∅