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Proof step 7 from proof crash-exists-h (previous step)

fid ∈ fs ⊦ ∃ fs0. (∀ fid0. fid0 ∈ fs0 ↔ fid0 = fid ∧ fid ∈ fs) ∧ (∀ fid. fid ∈ fs0 → fs0[fid] = fs[fid])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information