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Proof step 8 from proof crash-exists-h (previous step)

fid ∈ fs ⊦ ∃ fs0. (∀ fid0. fid0 ∈ fs0 ↔ fid0 = fid) ∧ (∀ fid. fid ∈ fs0 → fs0[fid] = fs[fid])

User applied rule exists right

And obtained the following new goals

Proof step 9:
fid ∈ fs ⊦ ∃ fs0. (∀ fid0. fid0 ∈ fs0 ↔ fid0 = fid) ∧ (∀ fid. fid ∈ fs0 → fs0[fid] = fs[fid]), (∀ fid0. fid0 ∈ (∅)[fid, fs[fid]] ↔ fid0 = fid) ∧ (∀ fid0. fid0 ∈ (∅)[fid, fs[fid]] → (∅)[fid, fs[fid]][fid0] = fs[fid0])

Rule argument

pos: right 1 terms: (∅)[fid, fs[fid]] abort: F discard: F computed: F

Additional information

Used terms: (∅)[fid, fs[fid]]