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Proof step 10 from proof inv-markbad (previous step)

apebs[n] = mkpeb(aehdr, avhdr, buf, m, false), n < # apebs, ubi-io-inv(apebs), ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪if err0 = ESUCCESS then apebs[n].bad := true⟫ ubi-io-inv(apebs)

Heuristic conditional right split applied rule if right

And obtained the following new goals

Rule argument

pos: right 1

Additional information