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Proof step 11 from proof inv-markbad (previous step)

apebs[n] = mkpeb(aehdr, avhdr, buf, m, false), err0 = ESUCCESS, n < # apebs, ubi-io-inv(apebs), ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪apebs[n].bad := true⟫ ubi-io-inv(apebs)

Heuristic symbolic execution applied rule assign right

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ ⌊ESUCCESS⌋ ; (s)%⊦ ubi-io-inv(apebs) → ( ubi-io-inv(apebs[n, apeb]) ↔ n < # apebs ∧ ubi-io-peb-inv(apebs[n]) → ubi-io-peb-inv(apeb)); (ss)%⊦ mkpeb(aehdr, avhdr, buf, m, boolvar).bad:= boolvar0 = mkpeb(aehdr, avhdr, buf, m, boolvar0); (s)%⊦ ubi-io-peb-inv(mkpeb(aehdr, avhdr, buf, n, true)) ↔ # buf = LEB_SIZE; (ss)%⊦ ubi-io-peb-inv(mkpeb(aehdr, avhdr, buf, n, boolvar)) → # buf = LEB_SIZE; (s)