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Theorem abs
⊦ abs(pebs, apebs) ↔ # pebs = # apebs ∧ (∀ n. n < # pebs → abs-peb(pebs[n], apebs[n]))
Type: An axiom
Validity: The proof is valid.
Features: ls,
Comment:
Used by:
abs-bad
,
abs-data-at
,
abs-fillcount-empty-echdr
,
abs-fillcount-empty-vidhdr
,
abs-fillcount-valid-headers
,
abs-fwd
,
abs-reduce
,
abs-reduce0
,
abs-size-apebs0
,
abs-size-apebs1
,
Used by units in proved state:
ubi-io-refine
,
Proof exists?: No