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Proof step 2 from proof inv-read-echdr (previous step)

m = EB_PAGE_SIZE, m0 < # pebs, mtd-cons(pebs) ⊦ ⟪ubi_io_read_echdr#(m0, m, pebs; aehdr; bitflips, err)⟫ true, pebs[m0].bad

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
m0 < # pebs, mtd-cons(pebs), ¬ pebs[m0].bad ⊦ ⟪ubi_io_read_echdr#(m0, EB_PAGE_SIZE, pebs; aehdr; bitflips, err)⟫ true

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic