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Proof step 3 from proof inv-read-echdr (previous step)

m0 < # pebs, mtd-cons(pebs), ¬ pebs[m0].bad ⊦ ⟪ubi_io_read_echdr#(m0, EB_PAGE_SIZE, pebs; aehdr; bitflips, err)⟫ true

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 4:
pebs[m0] = mkpeb(buf, m, boolvar), ¬ boolvar, m0 < # pebs, mtd-cons(pebs) ⊦ ⟪ubi_io_read_echdr#(m0, EB_PAGE_SIZE, pebs; aehdr; bitflips, err)⟫ true

Rule argument

spec: peb name: elim seq: ⊦ (buf = peb.data ∧ m = peb.fill) ∧ (boolvar ↔ peb.bad) ↔ peb = mkpeb(buf, m, boolvar) subst: [peb, buf, m, boolvar] → [pebs[m0], buf, m, boolvar]

Additional information

Used simplifier rules: ⊦ (buf = peb.data ∧ m = peb.fill) ∧ (boolvar ↔ peb.bad) ↔ peb = mkpeb(buf, m, boolvar); (elim) Used terms: pebs[m0], buf, m, boolvar