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Proof step 11 from proof initial-ex-abstract-initial (previous step)

m0 + 1 = # pebs, ubi-io-initial(pebs), m0 = # subarray(pebs, 0, m0) ∧ ubi-io-initial(subarray(pebs, 0, m0)) → (∃ apebs. abs(subarray(pebs, 0, m0), apebs) ∧ ubi-io-initial(apebs)) ⊦ ∃ apebs. abs(pebs, apebs) ∧ ubi-io-initial(apebs)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ # subarray(pebs, m, n) = n; (s)