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Proof step 12 from proof initial-ex-abstract-initial (previous step)

m0 + 1 = # pebs, ubi-io-initial(pebs), ubi-io-initial(subarray(pebs, 0, m0)) → abs(subarray(pebs, 0, m0), apebs) ∧ ubi-io-initial(apebs) ⊦ ∃ apebs. abs(pebs, apebs) ∧ ubi-io-initial(apebs)

User applied rule case distinction

And obtained the following new goals

Rule argument

pos: left 3

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