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Proof step 21 from proof initial-ex-abstract-initial (previous step)

m0 + 1 = # pebs, abs(subarray(pebs, 0, m0), apebs), ubi-io-initial(pebs), ubi-io-initial(apebs) ⊦ ∃ apebs. abs(pebs, apebs) ∧ ubi-io-initial(apebs)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information